MySQL基础练习题

  • Post category:MySQL

MySQL基础查询练习

前提准备

使用ddl语句创建数据库

student表格:

create table student(
	id int PRIMARY KEY COMMENT 'id主键',
	`name` varchar(20) COMMENT '名称',
	gender TINYINT(2) COMMENT '性别 1男 2女 3保密',
	age TINYINT UNSIGNED COMMENT '年龄',
	birthday date COMMENT '出生日期',
	createTime TIMESTAMP DEFAULT CURRENT_TIMESTAMP COMMENT '创建时间',
	updateTime TIMESTAMP DEFAULT CURRENT_TIMESTAMP COMMENT '更新时间' on update CURRENT_TIMESTAMP,
	isdel bit(1) DEFAULT 0 COMMENT '是否删除 0未删除 1已删除 默认未删除'
);

成绩表格score:

create table score (
	id int PRIMARY KEY COMMENT 'id主键',
	sid int COMMENT '学生id',
	course VARCHAR(20) COMMENT '课程名称',
	score DECIMAL(4,1) COMMENT '成绩'
);

因为下面插入数据没默认写id的值,所以id为自增的列。

添加自增:

alter table student
MODIFY column id int  auto_increment COMMENT 'id 主键';
alter table score
MODIFY column id int  auto_increment COMMENT 'id 主键';

初始化数据

数据下载地址:https://qyboke.lanzoue.com/iuhpB0n0rfij

score表:
在这里插入图片描述

student表格:

image-20230209145135111

答题

3.查询学生张三的所有成绩:

SELECT s.name,sc.course,sc.score from student s ,score sc where s.id = sc.sid and s.name = '李云';

4.查询平均成绩大于60的学生信息:

SELECT DISTINCT s.* from student s ,score sc where s.id = sc.sid and sc.score > 60;

5.查询有成绩的学生信息:

SELECT DISTINCT s.* FROM student s right JOIN score sc on s.id = sc.sid;

6. 查询不及格的学生信息:

SELECT DISTINCT s.* ,sc.course, sc.score
FROM student s right JOIN score sc 
on s.id = sc.sid
where sc.score < 60;

7. 查询各科成绩最高分、最低分和平均分:

SELECT DISTINCT score.course, max(score) over(PARTITION by score.course) '最高分',
min(score) over(PARTITION by score.course) '最低分',
avg(score) over(PARTITION by score.course) '平均分'
FROM score

8. 查询各科成绩第一名的记录:

SELECT DISTINCT sc.course, max(score) over(PARTITION by sc.course) '最高分'
FROM score sc left JOIN student s
on sc.sid = s.id

9. 查询男生、女生人数:

SELECT DISTINCT student.gender, count(student.gender) over(PARTITION by student.gender)
from student

10. 查询 1990 年出生的学生名单:

SELECT * from student where YEAR(birthday) = 1990;

11. 查询平均成绩大于等于 70 的所有学生的姓名、出生日期和平均成绩:

SELECT DISTINCT s.name,s.birthday,avg(sc.score) over(PARTITION by s.`name`) 
from score sc left JOIN student s
on sc.sid = s.id

12. 查询mbatis 成绩低于60的学生信息:

SELECT s.*,sc.course,sc.score
FROM score sc LEFT JOIN student s
on sc.sid = s.id
where sc.course = 'mybatis' and sc.score < 60;

13. 查询学生成绩前三名的记录:

SELECT ROW_NUMBER() over() as '成绩总分排名', sco.name,sco.allSco
FROM (
	SELECT DISTINCT s.`name` ,sum(sc.score) over(PARTITION by s.`name`) 'allSco'
from score sc LEFT JOIN student s
on sc.sid = s.id ORDER BY allSco desc LIMIT 3
) as sco

14. 查询学生信息及年龄:

SELECT stu.name,stu.birthday,(YEAR(CURRENT_DATE) - YEAR(stu.birthday)) '年龄'
from student stu

15. 按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩:

SELECT DISTINCT s.`name` ,sum(sc.score) over(PARTITION by s.`name`) 'allScore',avg(sc.score) over(PARTITION by s.name) '平均成绩'
from score sc LEFT JOIN student s
on sc.sid = s.id ORDER BY allScore desc

16. 查询未成年的学生信息:

SELECT stu.name, stu.birthday, (year(CURRENT_DATE) - year(birthday)) 'age'
from student stu
where (year(CURRENT_DATE) - year(birthday)) < 18

17. 查询姓张的 学生信息:

SELECT *
FROM student
where name like '张%'

18. 查询本月过生日的学生信息:

SELECT *
FROM student
where MONTH(CURRENT_DATE) = MONTH(birthday)

19. 查询本周过生日的学生信息

SELECT *
FROM student
WHERE WEEKOFYEAR(CURRENT_DATE) = WEEKOFYEAR(birthday)

20. 按各科成绩进行排序,并显示排名

SELECT stu.name , sc.course ,sc.score, RANK() over(PARTITION by sc.course ORDER BY sc.score desc)
from score sc LEFT JOIN student stu
on sc.sid = stu.id